x^2+250x-625=0

Solution for x^2+250x-625=0 equation:

x^2+250x-625=0

a = 1; b = 250; c = -625;
Δ = b2-4ac
Δ = 2502-4·1·(-625)
Δ = 65000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{65000}=\sqrt{2500*26}=\sqrt{2500}*\sqrt{26}=50\sqrt{26}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(250)-50\sqrt{26}}{2*1}=\frac{-250-50\sqrt{26}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(250)+50\sqrt{26}}{2*1}=\frac{-250+50\sqrt{26}}{2}
$